What is the heating surface area of a water tube with a diameter of 3 ½" and a length of 20 ft?

What is the heating surface area of a water tube with a diameter of 3 ½" and a length of 20 ft?

• A. 15.14 ft²
• B. 18.32 ft²
• C. 22.40 ft²
• D. 25.75 ft²

Answer: (B)

To determine the heating surface area of a water tube, we can use the formula for the surface area of a cylinder, which is given by: \[ \text{Surface Area} = \pi \times D \times L \] Where: - \(D\) is the diameter of the tube, - \(L\) is the length of the tube. In this scenario, the diameter is 3 ½ inches, which can be converted to feet for consistency in units: \[ 3.5 \text{ inches} = \frac{3.5}{12} \text{ feet} \approx 0.2917 \text{ feet} \] The length of the tube is given as 20 feet. Now, substituting these values into the formula: \[ \text{Surface Area} = \pi \times 0.2917 \text{ ft} \times 20 \text{ ft} \] Calculating this, we get: 1. Find the product of diameter and length: \( 0.2917 \times 20 \approx 5.834 \) 2. Now multiply by \(\pi\) (approximately 3.1416): \( 5.

To determine the heating surface area of a water tube, we can use the formula for the surface area of a cylinder, which is given by:

[ \text{Surface Area} = \pi \times D \times L ]

Where:

• (D) is the diameter of the tube,

• (L) is the length of the tube.

In this scenario, the diameter is 3 ½ inches, which can be converted to feet for consistency in units:

[ 3.5 \text{ inches} = \frac{3.5}{12} \text{ feet} \approx 0.2917 \text{ feet} ]

The length of the tube is given as 20 feet.

Now, substituting these values into the formula:

[ \text{Surface Area} = \pi \times 0.2917 \text{ ft} \times 20 \text{ ft} ]

Calculating this, we get:

1. Find the product of diameter and length:

( 0.2917 \times 20 \approx 5.834 )

2. Now multiply by (\pi) (approximately 3.1416):

( 5.